Chemistry Homework Help

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Photoelectric Effect

#### Q. Cesium metal is frequently used in photoelectric cells because the amount of energy necessary to eject electrons from a cesium surface is relatively small-only 206.5 kJ/mol. What wavelength of light (in nanometers) does this correspond to?

Solved • Oct 9, 2019

Photoelectric Effect

#### Q. What is the energy of each of the following photons in kilojoules per mole? λ = 262 m

Solved • Oct 9, 2019

Photoelectric Effect

#### Q. What is the energy of each of the following photons in kilojoules per mole? v = 5.99x10^19 s^-1

Solved • Oct 9, 2019

Photoelectric Effect

#### Q. Here are some data collected on a sample of cesium exposed to various energies of light. Light energy(eV) Electron emitted? Electron KE(eV) 3.87 no — 3.88 no — 3.89 yes 0 3.90 yes 0.01 3.91 yes 0.02 *1 eV (electron volt)=1.60×10−19 J. What is the threshold frequency ν0 of cesium? Express your answer numerically in hertz.

Solved • Oct 7, 2019

Photoelectric Effect

#### Q. A particular metal has a work function of 3.05 eV. A light is shined onto this metal with a corresponding wavelength of 524 nm. What is the maximum velocity of the photoelectrons produced? (Hint: 1eV = 1.6022 x 10^-19 J, mass of electron = 9.11 x 10^-31 kg) a) 8.72 x 10^8 m/s b) No photoelectrons are produced c) 8.32 x 10^11 m/s d) 9.12 x 10^5 m/s

Solved • Sep 24, 2019

Photoelectric Effect

#### Q. A particular metal has a work function of 1.05 eV. A light is shined onto this metal with a corresponding wavelength of 324 nm. What is the maximum velocity of the photoelectrons produced? (Hint: 1eV = 1.6022 x 10^-19 J, mass of an electron = 9.11 x 10^-31 kg) a) No photoelectrons are produced. b) 9.89 x 10^5m/s c) 1.35 x 10^12m/s d) 1.16 x 10^6m/s

Solved • Sep 24, 2019