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30 solutions

Combustion Analysis

Q. A compound has carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157 g of the compound produced 0.213 g CO2and 0.0310 g H2O. In another experiment, it is found that 0.103 g of the compound produces 0.0230 g NH3. What is the empirical formula.

Solved • Mar 10, 2020

Combustion Analysis

Q. A 0.4987-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.9267 g of CO2 and 0.1897 g of H2O. What is the empirical formula of the compound? A) CHO B) C2H2O C) C3H3O2 D) C6H3O2 E) C3H6O2

Solved • Mar 6, 2020

Combustion Analysis

Q. An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 7.00 g of this compound produced 10.3 g of carbon dioxide and 4.20 g of water. How many moles of carbon, C, were in the original sample? Express your answer to three significant figures include the appropriate units.

Solved • Feb 20, 2020

Combustion Analysis

Q. An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 7.00 g of this compound produced 10.3 g of carbon dioxide and 4.20 g of water. How many moles of hydrogen, H, were in the original sample? Express your answer to three significant figures include the appropriate units.

Solved • Feb 20, 2020

Combustion Analysis

Q. When 5.814 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 19.96 grams of CO2 and 3.270 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 128.2g/mol. Determine the empirical formula and the molecular formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. Empirical formula=

Solved • Feb 23, 2020

Combustion Analysis

Q. When 4.393 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.78 grams of CO2 and 5.044 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 70.13 g/mol. Determine the empirical formula and the molecular formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. Empirical formula=

Solved • Feb 23, 2020

Combustion Analysis

Q. Oxygen gas effuses 1.64 times faster than a carbon hydrogen compound that has an empirical formula of C3H7. what volume of oxygen will be used to burn 6.56*10^23 molecules of the carbon hydrogen compound in a combustion reaction at STP?

Solved • Feb 26, 2020