⚠️Our tutors found the solution shown to be helpful for the problem you're searching for. We don't have the exact solution yet.
A basketball star covers 2.80 m horizontally in a jump to dunk the ball (Fig. P4.24a). His motion through space can be modeled precisely as that of a particle at his center of mass which we will define in Chapter 9. His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.85 m above the floor and is at elevation 0.900 m when he touches down again. Determine (a) his time of flight (his "hang time") (b) his horizontal and (c) vertical velocity components at the instant of takeoff and (d) his takeoff angle. (e) For comparison determine the hang time of a whitetail deer making a jump (Fig. P4.24b) with center-of-mass elevations yi 5 1.20 m ymax 5 2.50 m and yf 5 0.700 m.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Projectile Motion: Positive Launch concept. If you need more Projectile Motion: Positive Launch practice, you can also practice Projectile Motion: Positive Launch practice problems.