Physics Practice Problems Refraction Of Light Practice Problems Solution: A person in the air above the water in a swimming ...

Solution: A person in the air above the water in a swimming pool looks straight down into the water (n = 1.33) at a diamond ring that lies on the bottom of the pool. If the image of the ring is 1.20 m below the surface of the water, what is the depth of the water (the distance from the surface of the water to the bottom of the pool)? Hint: Assume θ<<1, so sinθ=θ, and tanθ=θ, for a θ in radians. (a) 0.60 m (b) 0.90 m (c) 1.20 m (d) 1.60 m (e) 2.40 m (f) none of the above answers

Problem

A person in the air above the water in a swimming pool looks straight down into the water (n = 1.33) at a diamond ring that lies on the bottom of the pool. If the image of the ring is 1.20 m below the surface of the water, what is the depth of the water (the distance from the surface of the water to the bottom of the pool)? Hint: Assume θ<<1, so sinθ=θ, and tanθ=θ, for a θ in radians.

(a) 0.60 m

(b) 0.90 m

(c) 1.20 m

(d) 1.60 m

(e) 2.40 m

(f) none of the above answers