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Temperature | 22 mins | 0 completed | Learn |

Zeroth Law of Thermodynamics | 10 mins | 0 completed | Learn |

Thermal Expansion | 35 mins | 0 completed | Learn |

Introduction to Heat | 35 mins | 0 completed | Learn |

Changes in Temperature & Heat Capacity | 13 mins | 0 completed | Learn |

Changes in Phase & Latent Heat | 27 mins | 0 completed | Learn |

Temperature Change Across Phases | 25 mins | 0 completed | Learn |

Calorimetry | 23 mins | 0 completed | Learn |

Phase Diagrams, Triple Points and Critical Points | 11 mins | 0 completed | Learn |

Heat Transfer | 48 mins | 0 completed | Learn |

Solution: How much heat must be added to 0.00200 kg of ice at T = -60.0Â°C to produce 0.0020 kg of liquid water at 30.0Â°C? (Note: For ice, c = 2010 J/(kgâ˘K) and for liquid water cÂ = 4190 J/(kgâ˘K).Â For water, Â Lf

How much heat must be added to 0.00200 kg of ice at T = -60.0°C to produce 0.0020 kg of liquid water at 30.0°C? (Note: For ice, *c* = 2010 J/(kg•K) and for liquid water *c* = 4190 J/(kg•K). For water, *L*_{f }= 3.34 x 10^{5} J/kg and *L*_{v }= 2.256 x 10^{6} J/kg.)

(a) 5000 J

(b) 1420 J

(c) 1160 J

(d) 1030 J

(e) 909 J

(f) 493 J

(g) none of the above answers

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