Ch 22: Electric Force & Field; Gauss' LawWorksheetSee all chapters
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Ch 22: Electric Force & Field; Gauss' Law
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Solution: An electron traveling horizontally at 6 × 10 6 m/s enters a 0.05 m region with a uniform electric field of 89 N/C , perpendicular to the electron's velocity. The mass of an electron is 9.10939 × 10−31

Problem

An electron traveling horizontally at 6 × 10 6 m/s enters a 0.05 m region with a uniform electric field of 89 N/C , perpendicular to the electron's velocity. The mass of an electron is 9.10939 × 10−31 kg and the charge on an electron is 1.60218 × 10−19 C . What is the magnitude of the vertical displacement ∆y of the electron while it is in the electric field?

1. 0.00485434

2. 0.000543524

3. 0.0148796

4. 0.0649004

5. 0.00403356

6. 0.000873782

7. 0.00354891

8. 0.0176498

9. 0.00427393

10. 0.00586273