Problem: Consider a person whose eyes have a fully accommodated power of 56.5 D. Assume the distance from the lens to the retina is a fixed 2.00 cmWhat is the near point of that person in cm?

FREE Expert Solution

Power of a lens:

$\overline{){\mathbf{D}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{f}}}$

Lens maker equation:
$\overline{)\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{i}}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbit{f}}}$

Problem Details

Consider a person whose eyes have a fully accommodated power of 56.5 D. Assume the distance from the lens to the retina is a fixed 2.00 cm

What is the near point of that person in cm?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Thin Lens And Lens Maker Equations concept. You can view video lessons to learn Thin Lens And Lens Maker Equations. Or if you need more Thin Lens And Lens Maker Equations practice, you can also practice Thin Lens And Lens Maker Equations practice problems.