# Problem: Two 2.70 cm times 2.70 cm plates that form a parallel-plate capacitor are charged ± 0.708 nC.1. What is the electric field strength inside the capacitor if the spacing between the plates is 2.40 mm? 2. What is the potential difference across the capacitor if the spacing between the plates is 240 mm?

###### FREE Expert Solution

1.

Electric field due to the two parallel plates:

$\begin{array}{rcl}E& =& \frac{\mathbf{\sigma }}{\mathbf{2}{\mathbf{\epsilon }}_{\mathbf{0}}}\mathbf{+}\frac{\mathbf{\sigma }}{\mathbf{2}{\mathbf{\epsilon }}_{\mathbf{0}}}\\ & =& \frac{\mathbf{\sigma }}{{\mathbf{\epsilon }}_{\mathbf{0}}}\end{array}$

###### Problem Details
Two 2.70 cm times 2.70 cm plates that form a parallel-plate capacitor are charged ± 0.708 nC.
1. What is the electric field strength inside the capacitor if the spacing between the plates is 2.40 mm?
2. What is the potential difference across the capacitor if the spacing between the plates is 240 mm?