# Problem: The total translational kinetic energy of 1.0 mole of diatomic oxygen at 50°C is:Note that 1.0 mol of diatomic hydrogen at 50°C has a total translational kinetic energy of 4000 J.What is the correct total translational kinetic energy?

###### FREE Expert Solution

The rms speed and the translational kinetic energy are related by the expression:

$\overline{){{\mathbf{v}}}_{\mathbf{r}\mathbf{m}\mathbf{s}}{\mathbf{=}}\sqrt{\frac{\mathbf{2}{\mathbf{E}}_{\mathbf{k}}}{\mathbf{m}}}}$

Also, rms speed is:

$\overline{){{\mathbf{v}}}_{{\mathbf{rms}}}{\mathbf{=}}\sqrt{\frac{\mathbf{3}\mathbf{R}\mathbf{T}}{\mathbf{M}}}}$

The mass of the gas, m is calculated by:

m = (1.0)(32/1) = 32 g  of O2

###### Problem Details

The total translational kinetic energy of 1.0 mole of diatomic oxygen at 50°C is:
Note that 1.0 mol of diatomic hydrogen at 50°C has a total translational kinetic energy of 4000 J.

What is the correct total translational kinetic energy?