# Problem: You can double the maximum speed of an object on a spring undergoing simple harmonic motion by:a. Reducing the mass to one-fourth its original valueb. All of thesec. Doubling the amplituded. None of thesee. Increasing the spring constant to four times its original value

###### FREE Expert Solution

The maximum speed of an object on a spring undergoing a simple harmonic motion can be expressed as:

$\overline{){{\mathbf{v}}}_{\mathbf{m}\mathbf{a}\mathbf{x}}{\mathbf{=}}{\mathbf{\omega }}{\mathbf{A}}}$

But,

$\overline{){\mathbf{\omega }}{\mathbf{=}}\sqrt{\frac{\mathbf{k}}{\mathbf{m}}}}$

Therefore,

$\begin{array}{rcl}{\mathbf{v}}_{\mathbf{m}\mathbf{a}\mathbf{x}}& \mathbf{=}& \mathbf{\left(}\sqrt{\frac{\mathbf{k}}{\mathbf{m}}}\mathbf{\right)}\mathbf{A}\end{array}$

###### Problem Details

You can double the maximum speed of an object on a spring undergoing simple harmonic motion by:

a. Reducing the mass to one-fourth its original value

b. All of these

c. Doubling the amplitude

d. None of these

e. Increasing the spring constant to four times its original value