# Problem: Unpolarized light of intensity 30 W/cm2 is incident on a linear polarizer set at the polarizing angle θ1 = 23°. The emerging light then passes through a second polarizer that is set at the polarizing angle θ2 = 144°. Note that both polarizing angles are measured from the vertical. What is the intensity of the light that emerges from the second polarizer?

###### FREE Expert Solution

Intensity:

$\overline{){\mathbf{I}}{\mathbf{=}}{{\mathbf{I}}}_{{\mathbf{0}}}{\mathbf{c}}{\mathbf{o}}{{\mathbf{s}}}^{{\mathbf{2}}}{\mathbf{\theta }}}$

After passing through the first polarizer, the intensity of light is:

I1 = I/2 = 30/2 = 15 W/cm2

###### Problem Details

Unpolarized light of intensity 30 W/cm2 is incident on a linear polarizer set at the polarizing angle θ1 = 23°. The emerging light then passes through a second polarizer that is set at the polarizing angle θ2 = 144°. Note that both polarizing angles are measured from the vertical. What is the intensity of the light that emerges from the second polarizer?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Polarization Filters concept. You can view video lessons to learn Polarization Filters. Or if you need more Polarization Filters practice, you can also practice Polarization Filters practice problems.