Since the capacitor is charging:
In the given case, Q = Q0/4
t = 4.89056 × 10-6s
A 1.70-μF capacitor is charging through a 10.0-Ω resistor using a 10.0-V battery.
What will be the current when the capacitor has acquired 1/4 of its maximum charge? Will it be 1/4 of the maximum current?
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