Wavelength:

$\overline{){\mathbf{\lambda}}{\mathbf{=}}\frac{\mathbf{v}}{\mathbf{f}}}$

Wave speed in a string is:

$\overline{){\mathbf{v}}{\mathbf{=}}\sqrt{\frac{\mathbf{L}\mathbf{t}}{\mathbf{m}}}}$, where t is the tension on the spring.

**1.**

Frequency is given as f = 1/T

Therefore, the wavelength becomes:

λ = v/(1/T) = vT

An oscillator creates periodic waves on a stretched string.

1. If the period of the oscillator doubles, what happens to the wavelength and wave speed?

A. The wavelength doubles but the wave speed is unchanged.

B. The wavelength is halved but the wave speed is unchanged.

C. The wavelength is unchanged but the wave speed doubles.

2. If the amplitude of the oscillator doubles, what happens to the wavelength and wave speed?

A. The wavelength doubles but the wave speed is unchanged.

B. The wavelength is unchanged but the wave speed doubles.

C. Both wavelength and wave speed are unchanged.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Waves on a String concept. You can view video lessons to learn Waves on a String. Or if you need more Waves on a String practice, you can also practice Waves on a String practice problems.