Equivalent capacitance for capacitors in series:
The charge stored on a capacitor:
The 4.0 μF and the 6.0 μF capacitors are in series:
C4,6 = (1/C1 + 1/C2)-1 = (1/4 + 1/6)-1 = 2.4 μF(10-6F/1μF) = 2.4 × 10-6 F
The voltage across the two capacitors is 16 V.
Consider the circuit shown in (Figure 1). Assume E = 16 V. What is the charge on 4.0 μF capacitor? What is the charge on 6.0 μF capacitor?
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