The work done is equivalent to energy.

Therefore, the work can be compared to the kinetic energy.

W = ΔK

But, K = (1/2)mv^{2}

ΔK = (1/2)m(v_{f}^{2} - v_{i}^{2})

1 mph = 0.447 m/s

Which requires more work, increasing a carʹs speed from 0 mph to 30 mph or from 50 mph to 60 mph?

A. 50-60 mph

B. 0-30 mph

C. Same in both cases

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