# Problem: An amoeba is 0.305 cm away from the 0.300 cm focal length objective lens of a microscope. Randomized Variables: D = 19.93 cmfe = 2.14 cmPart (a) What is the image distance (in cm) for this configuration?Part (b) What is this image's magnification?Part (c) An eyepiece with a 2.14 cm focal length is placed 19.93 cm from the objective. What is the image distance for the eyepiece in cm?Part (d) What magnification is produced by the eyepiece?Part (e) What is the overall magnification?

###### FREE Expert Solution

Thins lens equation:

$\overline{)\frac{\mathbf{1}}{\mathbf{f}}{\mathbf{=}}\frac{\mathbf{1}}{{\mathbf{s}}_{\mathbf{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbf{s}}_{\mathbf{i}}}}$

Magnification:

$\overline{){\mathbf{m}}{\mathbf{=}}\frac{{\mathbf{h}}_{\mathbf{i}}}{{\mathbf{h}}_{\mathbf{o}}}{\mathbf{=}}{\mathbf{-}}\frac{{\mathbf{s}}_{\mathbf{i}}}{{\mathbf{s}}_{\mathbf{o}}}}$

(a)

For the objective lens:

f = 0.300 cm

so = 0.305 cm

si = (1/f - 1/so)-1 = (1/0.300 - 1/0.305)-1 = 18.3 cm.

###### Problem Details

An amoeba is 0.305 cm away from the 0.300 cm focal length objective lens of a microscope.

Randomized Variables:

D = 19.93 cm

fe = 2.14 cm

Part (a) What is the image distance (in cm) for this configuration?

Part (b) What is this image's magnification?

Part (c) An eyepiece with a 2.14 cm focal length is placed 19.93 cm from the objective. What is the image distance for the eyepiece in cm?

Part (d) What magnification is produced by the eyepiece?

Part (e) What is the overall magnification?