# Problem: Calculate the binding energy per nucleon for  238U___________MeV/nucleon

###### FREE Expert Solution

Binding energy:

$\overline{){\mathbf{B}}{\mathbf{E}}{\mathbf{=}}{\mathbf{∆}}{\mathbf{m}}{\mathbf{·}}{{\mathbf{c}}}^{{\mathbf{2}}}}$

c is the speed of light.

$\overline{){\mathbf{∆}}{\mathbf{m}}{\mathbf{=}}{\mathbit{Z}}{\mathbf{·}}{{\mathbf{m}}}_{{\mathbf{p}}}{\mathbf{+}}{\mathbit{N}}{\mathbf{·}}{{\mathbf{m}}}_{{\mathbf{n}}}{\mathbf{-}}{{\mathbf{m}}}_{\mathbf{a}\mathbf{t}\mathbf{o}\mathbf{m}}}$

Δm is the mass defect.

Mass of proton, mp = 1.007825 amu

Mass of neutron, mn = 1.008665 amu

Z = 92

N = (238 - 92) = 146

###### Problem Details

Calculate the binding energy per nucleon for  238U
___________MeV/nucleon