Ohm's law:

$\overline{){\mathbf{V}}{\mathbf{=}}{\mathbf{i}}{\mathbf{R}}}$

Equivalent resistance for series resistors:

$\overline{){{\mathbf{R}}}_{\mathbf{e}\mathbf{q}}{\mathbf{=}}{{\mathbf{R}}}_{{\mathbf{1}}}{\mathbf{+}}{{\mathbf{R}}}_{{\mathbf{2}}}}$

**(a)**

R_{eq} = R_{40} + R_{60} = 40 + 60 = 100Ω

i_{circuit} = ε/R_{eq} = 65/100 = 0.65 A

Suppose that ℰ = 65 V. (Figure 1)

What is the potential difference across the 40 Ω resistor? Express your answer with the appropriate units.

What is the potential difference across the 60 Ω resistor?

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