Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{E}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{m}}{{\mathbf{v}}}^{{\mathbf{2}}}}$

Potential energy:

$\overline{){\mathbf{U}}{\mathbf{=}}{\mathbf{m}}{\mathbf{g}}{\mathbf{h}}}$

Conservation of energy:

**KE _{0} + U_{0} = KE_{f} + U**

U_{f} = 0 (because h_{f} = 0)

- m = 1400 kg
- v
_{0}= 13.0m/s - h
_{0}= 5 m - g = 9.8 m/s
^{2}

(1/2)mv_{f}^{2} = (1/2)mv_{0}^{2} + mgh

A 1400 kg car is approaching the hill shown in the figure at 13.0m/s when it suddenly runs out of gas. (Figure 1)

What is the car's speed after coasting down the other side? in m/s

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