For the convex lens:
f = 5.0 cm
so = 4.0 cm
si = (sof)/(so - f) = (4.0 × 5.0)/(4.0 - 5.0) = -20 cm
For the concave lens:
f' = - 8 cm
1.) Find the position of the final image of the 1.0-cm-tall object
2.) Find the size of the final image of the 1.0-cm-tall object
3.) Is the object inverted or erect?
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