# Problem: The magnetic field of an electromagnetic wave in a vacuum is Bz = (2.4 µT)sin((1.14×107)x - ? t), where x is in m and t is in s.(a) What is the wave's wavelength?(b) What is the wave's frequency?(c) What is the wave's electric field amplitude?

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###### FREE Expert Solution

(a)

Wavelength:

$\overline{){\mathbf{\lambda }}{\mathbf{=}}\frac{\mathbf{2}\mathbf{\pi }}{\mathbf{k}}}$

Substituting:

λ = (2)(π)/(1.14 × 107) = 5.51 × 10-7m

The wave's wavelength is 5.51 × 10-7m.

###### Problem Details

The magnetic field of an electromagnetic wave in a vacuum is Bz = (2.4 µT)sin((1.14×107)x - ? t), where x is in m and t is in s.

(a) What is the wave's wavelength?

(b) What is the wave's frequency?

(c) What is the wave's electric field amplitude?