Impulse, J_{x} :

$\overline{){{\mathbf{J}}}_{{\mathbf{x}}}{\mathbf{=}}{{\mathbf{F}}}_{{\mathbf{x}}}{\mathbf{t}}}$

This implies that impulse is the area under the curve.

Area of a triangle = (1/2)by

In the figure, what value of F_{max} gives an impulse of 6.0 N**·**s?

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