🤓 Based on our data, we think this question is relevant for Professor Deslauriers' class at HARVARD.
Impulse is equal to the area under the curve. We'll sum the area enclosed by the three triangles.
Area of traingle,
For triangle A,
Base, b = (2 ms - 0 ms) = 2 × 10-3 s
Height, h = - 500 N
For triangle B,
Base, b = (8 ms - 2 ms) = 6 × 10-3 s
Height, h = 2000 N
What is the impulse on a 3.0 kg particle that experiences the force described by the graph in the figure?
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Based on our data, we think this problem is relevant for Professor Deslauriers' class at HARVARD.