# Problem: A force of 10 N acts on a charge of 5.0 μC when it is placed in a uniform electric field. What is the magnitude of this electric field?A) 1.0 MN/C B) 50MN/C C) 0.50 MN/C D) 1000 MN/C E) 2.0 MN/C

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###### FREE Expert Solution

Force due to a point charge is expressed as:

$\overline{){\mathbf{F}}{\mathbf{=}}{\mathbf{q}}{\mathbf{E}}}$

• F = 10 N
• q = 5.0 × 10-6C
• E = ? (magnitude of electric field).
###### Problem Details

A force of 10 N acts on a charge of 5.0 μC when it is placed in a uniform electric field. What is the magnitude of this electric field?

A) 1.0 MN/C

B) 50MN/C

C) 0.50 MN/C

D) 1000 MN/C

E) 2.0 MN/C