$\overline{){\mathbf{a}}{\mathbf{=}}\frac{\mathbf{q}\mathbf{r}}{\mathbf{2}\mathbf{m}}{\mathbf{\left|}}\frac{\mathbf{d}\mathbf{B}}{\mathbf{d}\mathbf{t}}{\mathbf{\right|}}}$

Here, q = 1.6 × 10^{-19} C, m = 1.67 × 10^{-27} kg, $\mathbf{\left|}\frac{\mathbf{d}\mathbf{B}}{\mathbf{d}\mathbf{t}}\mathbf{\right|}$ = 0.7 T/s, and r = $\mathbf{2}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{cm}\mathbf{\times}\frac{\mathbf{1}\mathbf{m}}{\mathbf{100}\mathbf{}\mathbf{cm}}$ = 2 × 10^{-2} m.

The magnetic field in the figure is decreasing at the rate of 0.7 T/s.

(a) What is the magnitude of the acceleration of a proton at rest at point **d**? Express your answer as an integer and include the appropriate units.

(b) What is the direction of the acceleration of a proton at rest at point **d**?

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