Direction for angles measured from the x-axis:
Resolving vector components:
r1 = (-16.0 i + 12 j ) m (the vector moves in the negative x-direction)
|r1| = 20 m
θ1 = tan-1 (r1y/r1x) = tan-1 (12/-16) = -36.9° (negative x-component shows that the angle is above the the negative x-axis).
From the positive x-axis:
θ1 = 180 - 36.9 = 143.1
r2 = (9 i + 12 j) m (the vector moves in the positive x-direction)
Two point charges are placed on the x-axis. The first charge, q1 = 8.00 nC, is placed a distance 16.0 m from the origin along the positive x-axis; the second charge, q2 = 6.00 nC, is placed a distance 9.00 m from the origin along the negative x-axis.
(a) Calculate the electric field at point A, located at coordinates (0 m, 12.0 m).
(b) Give the x and y components of the electric field as an ordered pair.
Express your answer in newtons per coulomb to three significant figures.
EAx, EAy =
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