$\overline{){\mathbf{v}}{\mathbf{=}}{\mathbf{f}}{\mathbf{\lambda}}}$

The resonant frequency for a pipe with one open end and one closed end is given by:

$\overline{){\mathbf{f}}{\mathbf{=}}\frac{\mathbf{n}\mathbf{v}}{\mathbf{4}\mathbf{L}}}$

Since L_{1} is greater than L_{2} and that they represent neighbouring resonances, then:

Using the two measured pipe lengths (L_{1} = 66cm and L_{2} = 40 cm), work out the wavelength of the sound wave. Use this to determine the mode numbers and speeds of sound that the two lengths correspond to. You can assume that L_{1} and L_{2} represent neighboring resonances (i.e, n and n+2). The pipes are open on one end and closed on the other. Frequency of tuning fork is 384 Hz.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Standing Sound Waves concept. You can view video lessons to learn Standing Sound Waves. Or if you need more Standing Sound Waves practice, you can also practice Standing Sound Waves practice problems.