⚠️Our tutors found the solution shown to be helpful for the problem you're searching for. We don't have the exact solution yet.

Solution: The gravitational attraction between two objects with masses m1 and m2, separated by distance x, is F=Gm1m2/x2, where G is the gravitational constant.How much work is done by gravity when the separation changes from x1 to x2? Assume x2<x1.If one mass is much greater than the other, the larger mass stays essentially at rest while the smaller mass moves toward it. Suppose a 1.5kg1013 kg comet is passing the orbit of Mars, heading straight for the 1.99kg1030 kg sun at a speed of 3.7 m/s104 G. What will its speed be when it crosses the orbit of Mercury? The orbit of Mars is 2.28m/s108 m km, the orbit of Mercury is 5.79km107 m km, and G = 6.67km10-11 m Ncdot m^2/kg^2.

Problem

The gravitational attraction between two objects with masses m1 and m2, separated by distance x, is F=Gm1m2/x2, where G is the gravitational constant.

How much work is done by gravity when the separation changes from x1 to x2? Assume x2<x1.

If one mass is much greater than the other, the larger mass stays essentially at rest while the smaller mass moves toward it. Suppose a 1.5kg1013 kg comet is passing the orbit of Mars, heading straight for the 1.99kg1030 kg sun at a speed of 3.7 m/s104 G. What will its speed be when it crosses the orbit of Mercury? The orbit of Mars is 2.28m/s108 , the orbit of Mercury is 5.79km107 , and = 6.67km10-11 .