Subjects

Sections | |||
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Magnetic Field Produced by Moving Charges | 11 mins | 0 completed | Learn |

Magnetic Field Produced by Straight Currents | 29 mins | 0 completed | Learn Summary |

Magnetic Force Between Parallel Currents | 13 mins | 0 completed | Learn |

Magnetic Force Between Two Moving Charges | 9 mins | 0 completed | Learn |

Magnetic Field Produced by Loops and Solenoids | 43 mins | 0 completed | Learn Summary |

Toroidal Solenoids aka Toroids | 12 mins | 0 completed | Learn |

Biot-Savart Law with Calculus | 16 mins | 0 completed | Learn |

Ampere's Law with Calculus | 17 mins | 0 completed | Learn |

Additional Practice |
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Ampere's Law |

Concept #1: Magnetic Field Produced by Straight Currents

**Transcript**

Hey guys so in this video we're gonna talk about how current in a wire will produce a magnetic field. Let's check it out. So you may remember that if you have a moving charge, that moving charge will produce a new field away from itself. So let's draw a little charge here, here and it's moving so it's got a v and that charge will produce a magnetic field up here or over here, right. In a number of different places away from itself. So and the magnitude of that magnetic field if you remember is mew not q v sine of theta divided by 4 pi r squared. But this is old news, that's why I said remember, right. And what we wanna talk about now is how just like moving charges will produce a new field well current will also produce a new field because current are just charges moving in a wire, right. So if you have a wire and it's got a current this way I, you can think of it as lots a little q's here that have v's. Right, lots of little q's with v's. That's what current is. So if a q moving with v produces a B field, than an I will also produce a B field. Okay, so current also produce new magnetic fields away from themselves. Okay, so if you have a current, just like up here you have a current I, you're also going to have a magnetic field somewhere over here and any number of distances. The magnitude of that equation looks a little cleaner than this one, a little nicer. It is that B equals mew not I divided by 2 pi r. And this equation is super important, you absolutely have to know this one. Okay. I mean you should know all the equations but this one is really really important, you're gonna see this all the time. I should know that this only works for a very very long wire and in most of the problems you're just going to assume that the little wire is very long even if it's not said, even if it's not stated. If you have a short wire, you're gonna get a different equation than this one, it's a little bit more complicated but most of you are gonna have to deal with that. Remember mew not is a constant and this r over here is a distance, little r is always the distance and never a radius. In fact if you have a wire it would be this right here r. Some people even us a letter d or sometimes a to make this equation. Cool. So that's how you find the magnitude and what about the direction. The direction comes from the right hand rule, and were gonna grab the wire with our thumb in the direction of current and this is pretty consistent with everything we've done so far which is you always want the thumb to be in the direction of the charges. The charges in the direction of which the charges are moving. Well the charges move in the direction of current so you're always gonna wanna use your thumb to point in that direction. Now what's gonna happen is we have a wire and I'm going to grab the wire in the direction right, so if the current is going to the left we're gonna grab it like this, but if the current is going to the right I'm gonna grab the wire like this. And by the way you're always going to use the right hand rule when you have wires. It's always the right hand rule, never the left hand rule because current is by convention positive. Cool. And then if you have 2 fields in the same location, and the fields are going in the same direction, we're going to add the magnetic fields and if they're going opposite directions we're going to subtract. And we'll see this in the second example so we'll get back to that one. In the first example we're just looking for the direction so we're gonna get to use this rule here and I'll show you how it works. So I wanna know what is the direction of the magnetic field produced by current in a very long wire if the current is oriented up. Meaning if you have a wire and the current's up like this, what is the direction of the magnetic field that is produced and what if you have a left current or what if you have it into the page current. Into the page, remember, means that it's going away from you so if you look at your sheet it's going away from you, right. Do it yourself so you follow and that means you're looking at the back of the arrow so you see an x and this is the symbol for into the page. Okay so imagine that this cable is going away from you like this, right, like that. Cool. So what happens with the direction of the magnetic field, well we're gonna grab the wire with my thumb pointing the direction of the current. So if I grab the wire with my thumb up, it's going to look like this, okay. Now this is super important and I'm actually gonna move it here so you can follow a little bit better. So this is super important, here is what we're going to do. This is going up which looks like this, this is the direction of the current so we wanna grab with my right hand always, I'm gonna grab it and then my hand should look like this. Please do this, please do this so that you can see. So what you're gonna do here is notice that my fingers are curling into the page here, into the page here, right. They're going like that direction away from my face into the page and when they come back around they come out of the page on the left side. Okay. So please I'm gonna do this really carefully hopefully you can follow. So into the page here and out of the page. Whenever your thumb is up you're always gonna get that effect. So what does that mean. When you are drawing it. Well what it means is that this is magnetic field anywhere to the right of the cable is gonna be into the page and anywhere here is going to be out of the page. Okay. So you can draw a bunch of little x's and dots. Cool. Now let's do left and I actually want you to do left and just as a hint, the top of the wire will be either an x or a dot and the bottom of the wire will be either an x or a dot. Figure out real quick, pause the video if you have to. Figure out real quick which one you think is which. You're gonna do the same thing I just did. I'm going to assume you paused the video and I'm gonna do it over here. So my thing is gonna be my current and into trhe right, I'm gonna grab it with my right hand which looks like this, right. Notice that my fingers are going into the page up here, and out of the page back here, okay. So what this looks like is what this looks like is into the page here and out of the page here. Cool. You gotta be good at this stuff. What about here, this is into the page so again I think you have a good chance of getting this right so just pause the video give it a shot, I'm gonna do it over here. And this is going into the page which means it's going away from you, right into the page. Please do this, grab like a pen or something and point it at the page which means my hand is gonna grab it like this. I'm actually gonna get rid of the pen, my hand is gonna grab it like this. So you should have your hand where your thumb is going into the page and if you do this, look what's happening with my curved fingers. Is that they're going in a clockwise direction. Trying to get the angle here right, so I'm gonna go in a clockwise direction. Please do this yourself, it looks like you gotta do it to make sure you're getting this right. So that means that actually the direction of the current is going, I'm sorry the direction of the magnetic field is this way. Okay. What if you had, what if you had the current coming out this way. Well obviously if the current flip directions than the magnetic field would flip direction as well. Okay. So in this case you would have your thumb pointing at you and you can't see it from my hand but if you look at your thumb, your hand with your thumb pointing at you like this, right. Looking really silly right now, you're gonna se that B goes counter clockwise. Hopefully you got that. Let's look at example 2 which is a computational example, it says 2 wires are shown below 4 meters away from each other. So this distance here is 4 meters and I wanna know what is the magnitude of the direction of the magnetic field that is produced at the center between the 2. The center between the 2 is somewhere over here, let's call this point p and it is a distance of 2 meters away from both of them and what I wanna know is essentially what is the magnetic field is the point p. I want the magnitude and the direction of the magnetic field. This is really the net magnetic field, that's gonna be a combination of 2 because this guy produces a magnetic field and this guy produces a magnetic field. They both produce a magnetic field there so really this is you could think of this as a net magnetic field so it's gonna be the magnetic field do to the 1st current plus the magnetic field do to the second current. I1 and I2. Except that these guys are going in different directions so they're gonna have different signs, okay. So we'll get to that in a little bit but essentially you're adding it's just that you might be adding a positive to a negative. Cool. So if you look at current 1 over here, it's got a dot so it means it's coming towards you and that means that the now it's coming towards you, current is my thumb towards me which means that the direction of the magnetic field is gonna be counter clockwise, okay so it's gonna create a magnetic field right at that point that's gonna be counter clockwise. So this is gonna be B 1 is counter clockwise and then B 2 is an x so it's going into the page. If it's going into the page it's going to be look at my fingers over here. If it's going into the page it's going to be clockwise. So please do this yourself, clockwise which means it's gonna go in this sort of direction, B 2 is going to be clockwise. They're going opposite directions and what we set up here is that if they're going opposite directions we're gonna subtract them. And that's because you're 1 is, you can think of 1 as being positive the other one is being negative and if you're adding them you have to subtract. So let's calculate B 1 and B 2 and then we'll figure out how to combine B 1 and B 2. So the equation is mew not I and by the way 1 divided by 2 pi r. One cute way to remember this is it spells moi so it's totally silly but B equals moi or if you wanna get fancy and French it's mou which is me I think, I don't know. So moi and maybe by making weird sounds I help you remember these equations, that's worth it. So B equals moi 2 pi r. Mew is 4 pi times 10 to the negative 7, the I if it's B 1 it's I 1 and r 1 so it's 3 amps divided by 2 pi. The distance is not 4, distance from this guy to the middle is 2 so look what's gonna happen here. The 4 cancels here, the pi cancels here so you're left with 3 times 10 to the negative 7 tesla. Because it's a magnetic field. What about this guy. B 2 is moi. Hopefully you don't have to say that out loud like me, people will think you're weird. 4 pi times 10 to the negative 7 the current is 5 divided by 2 pi and the distance is 2. Just plugging in the numbers, same thing happens the 4 cancels the pi cancels and now you're left with 5 times 10 to the negative 7 tesla. Now we want to combine the 2 and this is super important. Up here I wrote that you just add them but I really meant that you combine them okay which means you might have to actually subtract so you can think well B 2, B 2 is this clockwise B 1 is this counter clockwise, B 2 has the bigger magnitude so it wins, right and wins and then now you can just subtract and say B net is gonna be winner minus looser so 5 minus 3, big minus small which is 2. 2 times 10 to the negative 7 tesla and if this is the winning direction that's the final direction you get clockwise. Okay, that's one of the ways you can do this and that's the way I prefer just look at the big, if they're different just look at the big number, subtract the 2. Now another thing you should know is that you can assign a sign to these thing and you may remember from rotation that counter clockwise is actually the positive direction and clockwise is the negative direction so what you could have also have done is you could have said well B 1 means counter clockwise which is positive so it's positive 3 times 10 to the negative 7, B 2 is clockwise which makes it negative 5 times 10 to the negative 7 and then you can actually here just add the 2 and say that the net one is gonna be the addition of the 2. So you have a minus 7 with a plus 3 which gives you minus 2 times 10 to the negative 7 and minus means it is clockwise, okay. So you could have just look at the big one and said big minus small or you could have actually assigned signs to them and than based on right the sign coming from the direction and then the final sign also gives the direction. I wanna show you both because different professors different textbooks different way. Different people just prefer different things and they might understand differently. That's a lot of difference in one sentence. Alright guys, let's keep going.

Example #1: Find Field due to Two Perpendicular Currents

**Transcript**

Hey guys, so in this example we have two perpendicular wires and we want to find the magnetic field that they produce at a point, letÕs check it out. So it says two very long perpendicular, perpendicular again remember, it means 90 degrees, they intersect at (0,0). So this point right here where they cross is (0,0), and remember this is always (x position, y position). The vertical wire has a current of 2 A up, so this current right here is weÕre gonna call it I1 is 2 not 2 A, 2 _A, and then this current here is I2 which is 3 _A to the left. And we want to know whatÕs the net magnetic field at a point P located in this position here. So IÕm actually gonna extend this blue bar a little bit so we can draw it better, -4, -8, -9 would be somewhere over here, -4 means you are 4 away from the y-axis, so youÕre 4 to the left and -9 of course means that youÕre 9 down. So youÕre over here P(-4, -9) centimeters. Okay. And the reason it says net magnetic field is because there are two wires therefore there would be two magnetic fields produced here and we want to know whatÕs the result of combination of those two magnetic fields. Okay. So the magnetic field weÕre looking for would be a combination of magnetic field B1 which comes from current 1 and B2 which comes from current 2 and weÕll figure out when we combine the two. So the equation is B equals remember mua, right, _not I divided by 2 Pi r, but if IÕm looking for B1 it's I1 and r1 where r is the distance and for B2 is mua, 2, 2 Pi r2. And now weÕre just gonna plug all the numbers. So _not is 4 Pi times 10 to the negative 7, the current for 1 is 2 times 10 to the negative 6 because micro divided by 2 Pi (the distance), everything straight forward, the distance is the part here you have to pause a little bit and make sure you get the right number. So this B1 is coming from I1 so we have to look at the parallel distance or the shortest distance between wire 1 and point P. And the shortest distance is going to be right here. So this is going to be the distance which is a 4. Now I know it's a negative 4 but the gap, the distance between those 2 points is just going to be a positive 4. And thatÕs 4 centimeters, its 0.04 meters. Okay. And if you do this you will notice that the Pi cancels. There is a 4 here thatÕs gonna cancel with this 4, so this becomes a 1, this becomes a 0.01 and then the 2s also cancel, so youÕre left with 10 to the 7 times, negative 7, 10 to the negative 6 divided by 10 to the negative 2 down here and you can combine all this and you get 10 to the negative 11 or 1 times 10 to the negative 11 Tesla. Okay. So as we get there, letÕs calculate, weÕre going to talk about directions and see how we can combine, same thing IÕm going to do here 4 Pi 10 to the negative 7, the current is 3 _A and 2 Pi the distance is going to be, weÕre talking about B2, so weÕre looking at I2 and the distance here is 9, and again that distance is just a positive number, so its gonna be 0.09 meters because it's 9 centimeters. And if you do this, I have here, you get 0.67 times 10 to the negative 11 Tesla. Now, how they combine depends on your distance, on the directions. So what weÕre gonna do weÕre gonna grab wire, the first wire in the direction of car, so weÕll put a car going up and if I grab it notice how my fingers, and you have to do this yourself, donÕt look at me, or I guess look at me and do it yourself as well, to make sure that you get his right, because sometimes it looks weird in the camera. Right. So youÕre gonna grab the wire, and when you grab the wire, your fingers are going to be going into the page which is away from you, right, so I think itÕs going towards you but you need to look at your fingers how they are going away from you, on this side, right, with my thumb up, but when they come back around, cause P is over here, right, when they come back around, theyÕre coming towards you, so theyÕre coming out of the page. Okay. So wire 1 is gonna produce a B1 on this side everywhere right, thatÕs into the page. And then a B1 right here, everywhere that is out of the page. So at this point, B1 is going to be out of the page. Now I want you to do the same thing for, I want you to do the same thing for B2. What is the direction of B2, pause it if you have to, IÕm going to keep rolling here, IÕm gonna grab this wire, right, with my thumb to the right, and just look at here to see, on the top of the wire my fingers are going into the page, away from my face, itÕs towards you, because itÕs my fingers, right, and IÕm facing you, but if you do it yourself, its into the page and then when it comes back around because P is below here, right, when it comes back around it comes towards me. So B2 here, everywhere on top of this line, B2 is going to be into the page, but everywhere over here below this line, B2 is going to be out of the page. P is on this side, so B2 is below the line so B2 is also out of the page. And because both of these are the same direction, I can just add them and I can just say that the net magnetic field is the addition of these two guys here. So it's going to be 1.67 time 10 to the negative 11 Tesla. And that is the final answer. Cool. We took up this one. LetÕs keep going.

Example #2: Find Zero Magnetic Field

**Transcript**

Hey guys in this example we want to find where between two wires the magnetic field is zero, let's check it out. So we got two horizontal wires that are 6 meters away, they're both horizontal which means they're parallel. I'm gonna make the first one red and the second one blue and it says here the currents are 4A at the bottom, I'm gonna call that I2, 4A and 5A at the top and they're both going to the right. I1 equals 5A to look like this and their distance 6 meters away from each other and we will know where or how far from the bottom wire is the net magnetic field going to be equal to zero. So what I'm gonna do here first is look at the direction of these magnetic fields that will be produced by these currents. So if you have a wire and it points to the right you need to grab your right hand, right, your right hand right here and you're gonna grab it and it's going to be pointing, your thumb is going to be pointing the direction of current which means it has to look like this. Now if you go back and you go in again notice that my fingers under the wire are going into the plane away from me right, into the plane away from me and they come back around here towards me. Okay. So what that means is that I1 will generate an into the plane field at below it right so over here this is B1 due to wire 1 and then on top of the wire it's going to be towards me so I see a dot coming towards my face so that's gonna be B1. And by the way this extends out anywhere below the wire is going to have an XB field so if you keep going here this is also gonna be XB1 XB1. Just like how here keeps going this is a dots B1 dots B1. Okay. So it sort of a separation above and below the wire. Now if you do the same thing for wire 2, wire 2 is also going to the right, so you don't even have to grab the wire again, it's gonna do the same thing. Below the wire you're gonna have X, so X due to B2, X, i'm sorry, X direction of B2 due to this current and on top of the wire you gonna have a dots on top of the wire its coming towards you so this is gonna be B2 magnetic field due to current 2 and it's the same thing over here. Okay. So what this ends up creating is sort of three zones there's the top zone which is everything above the top wire, the bottom zone everything below the bottom wire and then there's this middle area here. Okay. And what you noticed when you have two wires going the same direction is that the net magnetic field at the top has to be out of the page towards you because they're both dots, they're gonna add up to be out of the page and over here the magnetic field at the bottom zone has to be into the page because both magnetic field produced by those two wires are going into the page which means that these guys can never be zero. Okay. The magnetic field will never be zero here, you can only get zero in the middle because that's where we have different directions we have opposite directions so Bnet here could be zero, is zero somewhere and where is it zero, well that's what we're trying to find out right. So the idea that there's a line here somewhere that is just the right distance between the top wire and the bottom wire so that the magnetic fields at that line cancel perfectly. Okay. And what we want to know is how far from the bottom wire that line is, so if you want you can call this distance A and I want to know what is A and you can call this distance B or we can call it we can also just call it r1 or r2 right, and this is r1 and what we're looking for for is r2 and by the way keep in mind that r1 plus r2 equals 6 meters, okay, equals 6 meters.Cool. So what do we do now, well, if we want the magnetic field to be zero this means that the magnitude of B1 equals the magnitude of B2. Two things with the same magnitude, same number but opposite directions will cancel themselves out perfectly. Okay. So what are the equations for B if you have a wire, its mua _not I divided by 2 Pi r, so we'll have this twice, now obviously the first case here were looking at B1 so this is current 1 and distance 1, current 2 and distance 2. Okay. These guys are just constants by the way so they get cancelled out which is nice, so you end up with I1/r1 = I2/r2 and we are looking for these numbers, we are looking for r2. Okay. Now if you notice I can quickly replace the I's, I's are 5 and 4, r2 is what I'm looking for, what about r1, so the problem with r1, is r2 is my variable that's what I'm looking for but I don't have r1 so what I have to do is I have to write an expression for r1, and if you look at r1 here, I can rewrite r1 as 6 minus r2 so 6 minus r2, and the good news here, is that here you have two unknowns. two variables and that's bad news with just one equation. Okay. Here you have one unknown which is good news. Now you can actually solve this. So now this is just an algebra problem, we have to cross multiply in getting our r2 solve for. So if I cross multiply 5r2 equals 4 times 6 minus r2 and I can expand this 5r2 equals 24 minus 4r2, I'm looking for r2 so I'm gonna move it over to the other side, 5 plus 4r2 is 9r2 equals 24, so r2 is 24 divided by 9 which is 2.7 meters. Okay. And that is the final answer. Would that means that this distance here is 2.7 meters? If the whole thing is 6 by the way it means that this is 3.3 meters. And it should make sense that the wire is a little closer to I2 than to I1 because the magnetic field comes from this equation. Notice that these two guys are constant, so they don't really matter right now. So the stronger my I, the stronger my B and the stronger my r the weaker my B. So the bottom one has a weaker I, has a smaller I, so to compensate for that, you also have to have a smaller r, so that its a little stronger, so the smaller I makes it weaker, but then the smaller r means that its closer which makes it stronger. Okay. So anyway weaker I means you want it to be closer which means you have a smaller r. Okay. And that would a bounce.That's it for this one, let's keep going.

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Concept #1: Magnetic Field Produced by Straight Currents

Example #1: Find Field due to Two Perpendicular Currents

Example #2: Find Zero Magnetic Field

The magnetic field at a certain distance from a wire carrying 2-A current is 4 μT. What will be the magnetic field if the current in the wire is doubled?
A) 8 μT
B) 6 μT
C) 4 μT
D) 2 μT

Three very long, straight, parallel wires each carry currents of 4 A, directed out of the page in the drawing in Figure 3. The wires pass through the vertices of a right isosceles triangle of side 2 cm. What is the magnitude of the magnetic field at point P at the midpoint of the hypotenuse of the triangle?

In the figure, the two long straight wires are separated by a distance of d = 0.40 m. The currents are I1 = 1.0 A to the right in the upper wire and I 2 = 8.0 A to the left in the lower wire. Find the magnitude and direction of the magnetic field at the center point O, and also point P, a distance d/2 = 0.20 m below the lower wire? (NOTE: μ0 = 4π x 10-7 T•m/A.)

A long straight wire carries a current of I = 3.00 A directed to the left, as shown in the sketch. A small sphere with negative charge q = -5.00 x 10-4 C is moving from the wire. When the sphere is 0.080 m from the wire, its speed is v = 9.00 m/s. What are the magnitude and direction of the magnetic field produced by the wire at the location of the sphere, 0.080 m below the wire? Write the direction in the blank provided and also show the direction on the sketch.
Ans. B =
direction =

A long straight wire carries a current of I = 3.00 A directed to the left, as shown in the sketch. A small sphere with negative charge q = -5.00 x 10-4 C is moving from the wire. When the sphere is 0.080 m from the wire, its speed is v = 9.00 m/s. What are the magnitude and direction of the force that the wire exerts on the small sphere when the sphere is at the position shown in the sketch? Write the direction in the blank provided and also show the direction on the sketch.
Ans. F =
direction =

The magnetic field created by a long straight wire carrying a current iA) decreases by a factor of four as the distance doubles.B) increases by a factor of four as the distance doubles.C) remains unchanged as the distance doubles.D) decreases by a factor of two as the distance doubles.E) increases by a factor of two as the distance doubles.

A very long straight current-carrying wire produces a magnetic field of 20 mT at a distance d from the wire. To measure a field of 5 mT due to this wire, you would have to go to distance of A) 2dB) 8dC) d√2D) 4dE) 16d

Two long straight parallel wires carry currents as shown in the sketch. Point A is midway between the two wires, 0.20 m from each wire. What are the magnitude and direction of the net magnetic field at point A due to the two wires?

A long, straight wire lies along the y-axis and carries current in the positive y-direction. A positive point charge moves along the x-axis in the positive x-direction. The magnetic force that the wire exerts on the point charge is inA. the positive x-direction.B. the negative x-direction.C. the positive y-direction.D. the negative y-direction.E. none of the above.

Two long wires carrying currents I 1 and I2 in the directions shown, with I 2 = 4I1, cross at right angles in the xy plane. Consider the points A = (2d, d) and B = (2d, −d), where d is a positive number. Find the ratio of the magnitudes of the magnetic fields at these two points, i.e., what is |BB/BA|?
A) 9/7
B) 1
C) 5/3
D) 4
E) None of these

The figure represents two long, straight, parallel wires carrying equal currents extending in a direction perpendicular to the page. The current in the right wire runs into the page and the current in the left runs out of the page.What is the direction of the magnetic field created by these wires at location a, b and c? (b is midway between the wires.)
1. down, zero, down
2. up, down, up
3. up, zero, up
4. down, down, up
5. up, zero, down
6. down, zero, up
7. down, up, down
8. up, up, down

Four long parallel wires each carry 10.0 A of current in the direction shown. The wires are at the corners of a square that is 10.0 cm on a side. What is the magnetic field at the center of the four wires?A. 0B. 1.13 x 10-4 TC. 5.66 x 10-5 TD. 8.00 x 10-5 TE. 2.00 x 10-5 T

In the figure below, the two long straight wires are separated by a distance of d = 0.40 m. The currents are I1 = 1.0 A to the right in the upper wire and I2 = 8.0 A to the left in the lower wire. What is the magnitude and direction of the magnetic field at point P, that is distance d/2 = 0.20 m below the lower wire?Note: μ0 = 4π x 10-17 T x m/AA. B = 7.7 x 10-6 T, directed into the plane of the page.B. B = 8.3 x 10-6 T directed into the plane of the page.C. B = 7.7 x 10-6 T directed out of the plane of the page.D. B = 8.3 x 10-6 T directed out of the plane of the page.

Two long parallel wires carry currents of 20 A and 5 A in opposite directions. The wires are separated by 0.20 m. What is the magnitude of the magnetic field midway between the two wires? (μ0 = 4π x 10-7 T•m/A)A) 3.0 x 10-5 TB) 1.0 x 10-5 TC) 2.0 x 10-5 TD) 4.0 x 10-5 TE) 5.0 x 10-5 T

The figure shows four different sets of insulated wires that cross each other at right angles without making electrical contact. The magnitude of the current is the same in all the wires, and the direction of current flow are as indicated. For which (if any) configuration will the magnetic field at the center of the square formed by the wires be equal to zero?
A) A
B) B
C) C
D) D
E) The field is not equal to zero in any of these cases.

At what distance from the central axis of a long straight thin wire carrying a current of 5.0 A is the magnitude of the magnetic field due to the wire equal to the strength of the Earth's magnetic field of about 5.0 x 10-7 T (μθ = 4π 10-7 T•m/A)A) 1.0 mB) 2.0 mC) 4.0 mD) 5.0 mE) 3.0 m

(a) What is the magnitude of the torque on the current loop in the figure? Express your answer using two significant figures.(b) What is the loop's equilibrium orientation?A. verticalB. horizontal

Two closed loops A and C are close to a long wire carrying a current(a) Find the direction (clockwise or counterclockwise) of the current induced in each loop if/is steadily decreasing.(b) While/ is decreasing, what is the direction of the net force that the wire exerts on each loop? Explain how you obtain your answer

A long straight horizontal wire carries a current = 2.10 A to the left. A positive 1.00 C charge moves to the right at a distance 1.50 m above the wire at constant speed = 2000 m/s . (Figure 1) A. What are the magnitude and the direction of the magnetic force on the charge?B. Select the source(s) responsible for the magnetic field that exerts a force on the moving charge?a) the chargeb) the current-carrying wirec) the charge and the current-carrying wire

Two parallel wires carry a current in the same direction. There is ___________ between the wires.A. a repulsive forceB. no forceC. an attractive force

What is the most convenient way to represent the niobium wire in your figure?A. In the plane of the paper with the current flowing horizontally.B. In the plane of the paper with the current flowing vertically.C. In the plane of the paper with the current flowing neither horizontally nor vertically.D. Perpendicular to the plane of the paper with the current flowing either into or out of the paper.E. Out of the plane of the paper, but not perpendicular to it.

Assume that I = 11 A .Part AWhat is the magnetic field strength at point a? Express your answer to two significant figures and include the appropriate units.Part BWhat is the direction of the magnetic field strength at point a?

Assume that I = 11 A .Part AWhat is the magnetic field strength at point b?Part BWhat is the direction of the magnetic field strength at point b?

Assume that I = 11 A .Part AWhat is the magnetic field strength at point c?Part BWhat is the direction of the magnetic field strength at point c?

Two long, straight, parallel wires, 10.0 cm apart carry equal 4.00-A currents in the same direction, as shown in the figure.Part AFind the magnitude of the magnetic field at point P1, midway between the wires.Part BWhat is the direction?a. to the leftb. to the rightc. upwardd. downwarde. no field

Four current carrying wires are arranged in the corners of a square as shown in the picture.Magnetic field in the center of the square is directed towards:

(a) What is the direction of the magnetic field at Point C? (b) What is the direction of the magnetic field at Point D? (c) What is the direction of the magnetic field at Point E?

Part A: Point M is located a distance from the midpoint between the two wires. Find the magnitude of the magnetic field created at point M by wire 1.Express your answer in terms of , , and appropriate constants.Part B: Find the magnitude of the net magnetic field created at point M by both wires.Express your answer in terms of , , and appropriate constants.

The figure shows a cross-section of three long straight current-carrying wires. Notice we are using the common convention that crosses denote vectors going into the page and dots denote vectors coming out of the page Part (a) Find the magnitude of the force per units length, in newtons per meter, on wire B.Part (b) Find the direction of the force for wire B, in degrees. Measure this angle counterclockwise, in degrees, from the positive x-axis.

The figure shows a cross-section of three long straight current-carrying wires. Notice we are using the common convention that crosses denote vectors going into the page and dots denote vectors coming out of the page Find the magnitude of the force per units length, in newtons per meter, on wire C.

The magnetic field lines due to a straight, current-carrying wire are __________.A. straight lines parallel to the wireB. circles around the wireC. straight lines perpendicular to the wire

A long wire carries current I. The wire is straight except for one square-shaped "half-loop" KLMN as shown (Figure 1). Assume that d is a known quantity.(a) Find the magnitude of magnetic field Bnet at point P. Express your answer in terms of some or all of the quantities d and /, and the constants μ0 and π.(b) Find the direction of the magnetic field at P.

The magnetic field 10 cm from a wire carrying a 1 A current is 2 μT. What is the field 4 cm from the wire? Express your answer with the appropriate units.

Two long, straight, parallel wires. 10.0 cm apart carry equal 4.00-A currents in the same direction. as shown in the figureFind the magnitude of the magnetic field at point P3, 20.0 cm directly above P1.What is its direction?A) to the left B) to the right C) upward D) downwardE) no field

Part B) Two long thin parallel wires 13.0 cm apart carry 25-A currents in the same direction. Determine the magnitude of the magnetic field vector at a point 10.0 cm from one wire and 6.0 cm from the other (Figure 1).

What creates a magnetic field? More than one answer may be correct.a. a stationary conductor carrying electric currentb. a moving object with electric chargec. a difference in electric potentiald. a charged capacitor disconnected from a battery and at reste. a stationary object with electric charge

MEASURING EARTH'S MAGNETIC FIELDThe goal of this section of the lab is to measure the Earth's magnetic field. Since the β-field produced by the Earth is a vector, it has a magnitude and a direction. You have already measured the direction of the Earth's β-field, so all that is left to measure is its magnitude. By introducing another magnetic field (produced by the coil of wire attached to the wooden box) and using the compass, you will be able to measure the total magnetic field (Earth and wire fields combined), and use that information to infer the magnitude of the Earth's field alone.Practical considerations restrict the current to about 2.0 A. To overcome this we have multiple wires running parallel to each other, each carrying about 2.0 A. This setup also has a platform where you can place a sheet of paper and a compass. You can mark the angle of the compass needle on the paper.E1. Before you connect the loops of wire to the supply, set the current limit of the supply to its maximum value, and set the voltage to 2.5 V. ( This is just to make sure there is not too much current in the wires when you turn the supply on.) Then switch the supply to read current, and turn the power supply off. Cut a sheet of paper to fit around the wire and rest on the platform to record the direction of the magnetic field. Set up the circuit so that the "conventional" current is flowing upwards.E2. Test your setup: turn the power supply on and verify that you get a current of about 2.0 A. (This may not correspond to 2.5 V, which is ok) Do not leave the supply for about 2.0 A. (This may correspond to 2.5 V, which is ok) Do not leave the supply on for more than 10 seconds to avoid overheating. Note the current and the number of wires in your setup. DATA (3):(a) Draw a top-down diagram of your setup of image provided: I is current passing through wire; arrows are vectors of compass pointing. This diagram should include: - The direction of current in the wires- The direction of the compass needle- Vectors representing the Earth's magnetic field and the magnetic field of the wire at the location of the compass- Known and relevant distances, angles, and currents- The cardinal directions (N,S,E,W)Use your measurements from part E to calculate the strength of the Earth’s magnetic field. Show your work.Measurement: 2.5-A current through wire pointing upwards (down to up), an angle the needle makes on compass (north pointing towards wire) when current is 2.5: 37° +/- 3°. Distance of needle of compass to wire: (2.1 +/- 0.5) cm. hint: tanθ = Bwire/BEarth.Calculate the uncertainty in your measurement of the Earth's magnetic field.Compare your measured magnetic field and uncertainty to the official range of values for the Earth's surface magnetic field. Are your measurements consistent with the official values?

Find the direction of the magnetic field at each of the indicated points.What is the direction of the magnetic field Bc at Point C?A. Bc is out of page.B. Bc is into the pageC. Bc is neither out of nor into the page and Bc ≠ 0.D. Bc = 0.

The diagram shows the cross section of wire carrying conventional positive current into the plane of the page. (You may ignore the earth's magnetic field)A) By means of an arrow on the diagram, show the direction in which a compass would point if placed at location A and describe the rule you use to remember this effect.B) Show the direction in which the compass would point at two other points of your own choosing.

Shown at the right is a cross-sectional view of two long straight wires that are parallel to one another. One wire carries current io out of the page, the other carries an equal current into the page.Draw a vector on the diagram to show the direction of the magnetic field, if any, at point P. Explain your reasoning.

A long, straight wire extends into and out of the screen. The current in the wire isa) Out of the screen.b) There is no current in the wire.c) Into the screen.d) There is not enough information to tell the direction.

What is the direction of the magnetic field Bc at Point C?a. Bc is out of the pageb. Bc is into the pagec. Bc is neither out of nor into the page and Bc ≠ 0d. Bc = 0

A steady current I is flowing through a straight wire of finite length.Part AFind B1, the magnitude of the magnetic field generated by this wire at a point P located a distance x from the center of the wire. Assume that at P the angle subtended from the midpoint of the wire to each end is θm as shown in the diagram (Figure 1).

A steady current I is flowing through a straight wire of finite length. Now find B2, the magnetic field generated by this wire at a point P located a distance x from either end of the wire. Assume that at P the angle subtended from the end of the wire to the other end is θend as shown in the diagram.

Two wires lie perpendicular to the plane of the paper, and equal electric currents pass through the paper in the directions shown. Point P is equidistant from the two wires.Construct a vector diagram showing the direction of the resultant magnetic field at point P due to currents in these two wires. Explain your reasoning,

Two wires lie perpendicular to the plane of the paper, and equal electric currents pass through the paper in the directions shown. Point P is equidistant from the two wires.If the currents in both wires were instead directed out of the plane of the page (such that the current moved toward us), show the resultant magnetic field at point P.

A long, straight wire lies along the y-axis and carries a current 8.00 A in the -y-direction (Figure 1). In addition to the magnetic field due to the current in the wire, a uniform magnetic field Bapp with magnitude 1.50×10−6 T is in the +x-direction.What is the magnitude of the total field at the point x = 0, z = 1.00 m in the xz-plane?

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