🤓 Based on our data, we think this question is relevant for Professor Hersh's class at QC CUNY .
We’re being asked to determine the stereochemistry of the given compound.
We can see that this is a chiral molecule because:
– there is no plane of symmetry present
– there is a chiral center present
Recall that the R/S configuration gives us the absolute stereochemistry of chiral centers. It involves:
1. Determining the priority of groups at the chiral center.
• Priority is determined using atomic mass.
• If the same atom is present, we compare the other atoms it is bonded to.
– Double and triple bonds count twice/thrice.
2. Determining the R/S configuration of the chiral center.
• If the lowest priority is on a dashed line: trace a path from 1 to 3
– If the order is clockwise → R (rectus or right)
– If the order is counterclockwise → S (sinister or left)
• If the lowest priority is not on a dashed line: swap with the group on a dashed line
– Trace a path from 1 to 3:
– Clockwise → R becomes S because of the swap
– Counterclockwise → S becomes R because of the swap
Select the correct (R) or (S) designation for the stereocenter carbon atom in the following molecule.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the R and S Configuration concept. You can view video lessons to learn R and S Configuration. Or if you need more R and S Configuration practice, you can also practice R and S Configuration practice problems.
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Based on our data, we think this problem is relevant for Professor Hersh's class at QC CUNY .