Solution: The iodination of ethylene at 25°C is characterized by the thermodynamic values shown.H2C = CH2(g) + I2(g) ⇌ lCH2CH2l(g)     ΔH° = - 48 kJ/mol; ΔS° = - 0.13 kJ/mol(c) What happens to K as the temperature is raised?

Problem

The iodination of ethylene at 25°C is characterized by the thermodynamic values shown.

H2C = CH2(g) + I2(g) ⇌ lCH2CH2l(g)     ΔH° = - 48 kJ/mol; ΔS° = - 0.13 kJ/mol

(c) What happens to K as the temperature is raised?