Nucleophile → OH-
Leaving group → 1° alkyl bromide
Elimination (E2-mechanism) for this reaction will appear as:
Which of the following are the elimination products of the reaction shown below?
CH3CH2Br + -OH →
A) CH3CH2Br + H + O-
C) CH3CH2OH + Br-
D) CH2=CH2 + Br- + H2O
E) CH2=CHBr + H2O
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