Problem: The mass spectrum of diisopropyl ether is shown below:1. Draw the radical cation giving the molecular ion. Be sure to include the nonbonding electrons on the oxygen.2. Identify the fragment giving rise to the peak at m/z = 87. Be sure to include the nonbonding electrons on the oxygen.

🤓 Based on our data, we think this question is relevant for Professor Portmess' class at UF.

FREE Expert Solution

For diisopropyl ether in mass spec analysis, O will lose 1 lone pair which will give us the molecular ion as:

  • For this molecule, molecular ion is around m/z = 102. 
  • For m/z = 87, this appears to have lost m/z =15 (102 - 87 = 15). 
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Problem Details

The mass spectrum of diisopropyl ether is shown below:

1. Draw the radical cation giving the molecular ion. Be sure to include the nonbonding electrons on the oxygen.

2. Identify the fragment giving rise to the peak at m/z = 87. Be sure to include the nonbonding electrons on the oxygen.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mass Spect: Fragmentation concept. You can view video lessons to learn Mass Spect: Fragmentation. Or if you need more Mass Spect: Fragmentation practice, you can also practice Mass Spect: Fragmentation practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Portmess' class at UF.