** Index of hydrogen deficiency (IHD) **→ # of missing H's in structure:

$\overline{){\mathbf{IHD}}{\mathbf{=}}\frac{\mathbf{[}\mathbf{2}\mathbf{n}\mathbf{+}\mathbf{2}\mathbf{]}\mathbf{-}\mathbf{H}}{\mathbf{2}}}$

where **n = number of carbons** and **H** is:

• **+1** for *hydrogen (H) or halogens (X)*

• **0** for *oxygen (O)*

• **–1** for *nitrogen (N)*

Given:**C _{6}H_{12}O**

$\mathbf{IHD}\mathbf{=}\frac{\mathbf{[}\mathbf{2}\left(6\right)\mathbf{+}\mathbf{2}\mathbf{]}\mathbf{-}\mathbf{12}}{\mathbf{2}}$

**IHD = 1 → ring or double bond**

IR spectra: 1735 cm^{-1}→ **ester (**RCOOR: 1735-1750 cm^{-1}) → **double bond ****(C=O**)

Provide a structure for the following compound:

C_{6}H_{12}O_{2}:

IR: 1743 cm^{-1};

^{1}H NMR spectrum:

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Structure Determination without Mass Spect concept. You can view video lessons to learn Structure Determination without Mass Spect. Or if you need more Structure Determination without Mass Spect practice, you can also practice Structure Determination without Mass Spect practice problems.