Problem: Identify the following compound:C5H10ONMR: δ 9.8 (1 H, s), δ 1.1 (9 H, s)

FREE Expert Solution

Degree of unsaturation, IHD:


IHD=(2C-N+H)+22

IHD=(2(5)-0+10)+22

IHD = 1 → double bond or ring

  • NMR:
    • C-H  δ = 1 - 2 
      • δ = 1.1 9 H singlet 3 methyl groups (CH3)
    • Adehyde -CHO  δ = 9 - 10
      • δ = 9.8 1 H, singlet  → CH
      • 1 O C = O (carbonyl)
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Problem Details

Identify the following compound:
C5H10O

NMR: δ 9.8 (1 H, s), δ 1.1 (9 H, s)

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