Reaction: CaCO3(aq) + HCl(aq) → CaCl2(aq) + H2CO3(aq)
H2CO3 decomposes to H2O(l) + CO2(g)
Reaction: CaCO3(aq) + 2 HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)
Calculate the moles HCl:
moles HCl = 0.03105 mol
Calculate the moles excess HCl:
HCl + NaOH → NaCl + H2O
moles excess acid = moles NaOH used for neutralization
moles excess HCl = 0.0116756 mol
A 1.130 g sample of limestone rock is pulverized and then treated with 30.00 mL of 1.035 M HCl solution. The excess acid then requires 11.56 mL of 1.010 M NaOH for neutralization.
You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem.
Calculate the percent by mass of calcium carbonate in the rock, assuming that it is the only substance reacting with the HCl solution.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Equivalence Point concept. If you need more Equivalence Point practice, you can also practice Equivalence Point practice problems.