Problem: The distinctive odor of vinegar is due to acetic acid, CH3COOH, which reacts with sodium hydroxide in the following fashion:CH3COOH(aq) + NaOH(aq)(l) + NaC2H3O2 (aq)You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem.If 3.55 mL of vinegar needs 43.0 mL of 0.130 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.60 qt sample of this vinegar?

FREE Expert Solution

Recall that at the equivalence point of a titration:


moles acid=moles base


Also, recall that:

  • moles = molarity × volume
  • moles = mass/ molar mass


This means:


(MV)acid=MVbase


Solving for Macid:


Macid3.55 mL=0.130 MNaOH43.00 mL


Macid=(0.130 MNaOH)(43.00 mL)3.55 mL = 1.575 M

View Complete Written Solution
Problem Details

The distinctive odor of vinegar is due to acetic acid, CH3COOH, which reacts with sodium hydroxide in the following fashion:
CH3COOH(aq) + NaOH(aq)(l) + NaC2H3O2 (aq)

You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem.

If 3.55 mL of vinegar needs 43.0 mL of 0.130 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.60 qt sample of this vinegar?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Equivalence Point concept. If you need more Equivalence Point practice, you can also practice Equivalence Point practice problems.