We have to calculate the mass of silver chloride required to plate out 215 mg of pure silver.

The **mass percent of an element** in a compound can be calculated using this formula:

$\overline{){\mathbf{Mass}}{\mathbf{}}{\mathbf{percent}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{element}}{\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{compound}}{\mathbf{\times}}{\mathbf{100}}{\mathbf{}}{\mathbf{\%}}}$

**For silver and silver chloride, the formula can be changed as:**

$\overline{){\mathbf{Mass}}{\mathbf{}}{\mathbf{percent}}{\mathbf{}}{\mathbf{of}}{\mathbf{}}{\mathbf{silver}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{silver}}{\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{silver}\mathbf{}\mathbf{chloride}}{\mathbf{\times}}{\mathbf{100}}{\mathbf{}}{\mathbf{\%}}}$

Silver chloride, often used in silver plating, contains 75.27% Ag.

Calculate the mass of silver chloride required to plate 215 mg of pure silver.

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