🤓 Based on our data, we think this question is relevant for Professor Woolman's class at MSCD.
The amount of energy (q) needed to freeze a given mass is calculated using:
n = number of moles
ΔHvaporization = heat of vaporization (in J/mol)
m = 422 g
ΔHvaporization = 40.65 kJ/mol
Since we are given the mass of liquid water, we need to determine the number of moles of water.
The molar mass of H2O is 18.016 g/mol.
How much heat is required to convert 422 g of liquid H2O at 23.5 °C into steam at 150 °C?