Problem: Arrange the following ACln species in order of  decreasing  Cl—A—Cl bond angles:SCl2, OCl2, PCl3, SiCl4, SiCl62−.

🤓 Based on our data, we think this question is relevant for Professor Davidson's class at UTSA.

FREE Expert Solution

Electron Regions          Electronic Geometry          Bond Angles

2                                      linear                                    180˚

3                                      trigonal planar                      120˚

4                                      tetrahedral                            109.5˚

5                                      trigonal bipyramidal              90˚, 120˚, and 180˚

6                                      octahedral                            90˚ and 180˚


Lone pairs are treated as electron regions. 

The lone pairs in the central atom will make the bond angles smaller than expected. 


A) SCl

  • S → group 6A → 2 lone pairs
  • 2 LP + 2 atoms = 4 regions → tetrahedral
  • <109.5°

B) OCl2

  • S → group 6A → 2 lone pairs
  • 2 LP + 2 atoms = 4 regions → tetrahedral
  • <109.5°

C) PCl3

  • P → group 5A → 1 lone pair
  • 1 LP + 3 atoms = 4 regions → tetrahedral
  • <109.5° but larger than first two since only 1 lone pair. 


D) SiCl4 

  • Si → group 4A → 0lone pairs
  • 4 atoms = 4 regions → tetrahedral
  • 109.5°


View Complete Written Solution
Problem Details

Arrange the following ACln species in order of  decreasing  Cl—A—Cl bond angles:

SCl2, OCl2, PCl3, SiCl4, SiCl62−.