Problem: The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6.0×10−3 mm .If a single gold atom has a diameter of 2.9×10-8 cm, how many atoms thick was Rutherford's foil?

🤓 Based on our data, we think this question is relevant for Professor Billman's class at Abilene Christian University.

FREE Expert Solution

We have to determine how many gold atoms thick was the gold foil used in Rutherford’s gold foil experiment.


To determine the thickness of gold foil in number of atoms, we can use the dimensional analysis.

We will first convert the thickness of foil from mm units to cm unitsso that the units can cancel out when we determine the number of gold atoms.

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Problem Details

The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6.0×10−3 mm .

If a single gold atom has a diameter of 2.9×10-8 cm, how many atoms thick was Rutherford's foil?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gold Foil Experiment concept. You can view video lessons to learn Gold Foil Experiment. Or if you need more Gold Foil Experiment practice, you can also practice Gold Foil Experiment practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Billman's class at Abilene Christian University.