Problem: The gold foil that Rutherford used in his scattering experiment had a thickness of approximately 0.006 mm .If a single gold atom has a diameter of 2.9 10-10 m, how many atoms thick was Rutherfords foil?

🤓 Based on our data, we think this question is relevant for Professor Snaddon's class at IU.

FREE Expert Solution
  • We can calculate for how many atoms thick the foil is by dividing the thickness of gold foil by the diameter of a gold atom
  • Setup a dimensional analysis with proper length conversion to determine the # of atoms
View Complete Written Solution
Problem Details

The gold foil that Rutherford used in his scattering experiment had a thickness of approximately 0.006 mm .

If a single gold atom has a diameter of 2.9 10-10 m, how many atoms thick was Rutherfords foil?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gold Foil Experiment concept. You can view video lessons to learn Gold Foil Experiment. Or if you need more Gold Foil Experiment practice, you can also practice Gold Foil Experiment practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Snaddon's class at IU.