🤓 Based on our data, we think this question is relevant for Professor Liwosz's class at UB.

**Step 1.** convert:

10^{-2} m = 1 cm

$\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{15}}\mathbf{}\overline{)\mathbf{m}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{cm}}{{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\overline{)\mathbf{m}}}\mathbf{=}$** 1.0 x 10 ^{–13} cm **

1 amu = 1.66 x 10^{-24 }grams

$\mathbf{1}\mathbf{.}\mathbf{0073}\mathbf{}\overline{)\mathbf{amu}}\mathbf{\times}\frac{\mathbf{1}\mathbf{.}\mathbf{66}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{24}}\mathbf{}\mathbf{g}}{\mathbf{1}\mathbf{}\overline{)\mathbf{amu}}}\mathbf{=}$** 1.67 x 10 ^{–24} g **

Using the mass of the proton 1.0073 amu and assuming its diameter is 1.0x10^{ - 15} m, calculate the density of a proton in g/cm^{3}.

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Based on our data, we think this problem is relevant for Professor Liwosz's class at UB.