Problem: Hydrogen and oxygen form both water and hydrogen peroxide. A decomposition of a sample of water forms 0.125 g hydrogen to every 1.00 g oxygen. The decomposition of a sample of hydrogen peroxide forms 0.0625 g hydrogen to every 1.00 g oxygen.Show that these results are consistent with the law of multiple proportions.

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FREE Expert Solution
  • Law of Multiple Proportions states that "When two elements form a series of compounds, the ratio of the masses of the 1st element that combine with 1 g of the other element can always be reduced to small whole numbers"

  • In order to confirm the Law of Multiple Proportions here, we need to  calculate the mass of H over mass of O to find how much g of H is in 1 g of O

  • Hydrogen peroxide is composed of a peroxide ion (O22-) and 2 H+ atoms. Recall that compounds, the charge of the ion goes to the subscript of the counterion. Hydrogen peroxide will appear as H2O2

  • Calculating the proportions of H and O for water and hydrogen peroxide:

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Problem Details

Hydrogen and oxygen form both water and hydrogen peroxide. A decomposition of a sample of water forms 0.125 g hydrogen to every 1.00 g oxygen. The decomposition of a sample of hydrogen peroxide forms 0.0625 g hydrogen to every 1.00 g oxygen.

Show that these results are consistent with the law of multiple proportions.