# Problem: The ratio of the mass of O to the mass of N in N2O3 is 12:7. Another binary compound of nitrogen has a ratio of O to N of 16:7.What is the ratio of O to N in the next member of this series of compounds?

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We’re being asked to determine the ratio of O to N in the next member of the given series of compounds.

We’re given the ratio of oxygen (O) to nitrogen (N) by mass in dinitrogen trioxide (N2O3) is 12:7

Furthermore, we are given a compound with a ratio of oxygen (O) to nitrogen (N) by mass of 16:7.

According to the Law of Multiple Proportions, when two elements (A & B) form different compounds, the masses of element B that combine with 1 g of A are a ratio of whole numbers.

Given: ###### Problem Details

The ratio of the mass of O to the mass of N in N2O3 is 12:7. Another binary compound of nitrogen has a ratio of O to N of 16:7.

What is the ratio of O to N in the next member of this series of compounds?