Ch.9 - Bonding & Molecular StructureWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Sections
Chemical Bonds
Lattice Energy
Lattice Energy Application
Born Haber Cycle
Dipole Moment
Lewis Dot Structure
Octet Rule
Formal Charge
Resonance Structures
Additional Practice
Bond Energy

Solution: Identify the molecules with a dipole moment:(a) SF4(b) CF4(c) Cl2CCBr2(d) CH3Cl(e) H2CO

Problem

Identify the molecules with a dipole moment:
(a) SF4
(b) CF4
(c) Cl2CCBr2
(d) CH3Cl
(e) H2CO

Solution

For a molecule to have a dipole moment, the individual dipole moments of its bonds must not cancel out.

(a) SF: The Lewis structure for SF4 is:

Sulfur (2.58) is less electronegative than fluorine (3.98), which means the S–F bond has a dipole moment. Since the central atom S also has a lone pair, there's also a dipole arrow pointing away from it. The dipole arrows in SF4 would look like this:

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