Ch.6 - Thermochemistry WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Given the following dataP4 (s) + 6Cl2 (g) → 4PCl3 (g)      ΔH = -1225.6 kJP4 (s) + 5O2 (g) → P4O10 (s)      ΔH = -2967.3 kJPCl3 (g) + Cl2 (g) → PCl5 (g)      ΔH = -84.2 kJPCl3 (g) + 1/2 O2 (g) → Cl3PO (g)    ΔH = -285.7 kJcalculate ΔH for the reactionP4O10 (s) + 6PCl5 (g) → 10Cl3PO (g)

Solution: Given the following dataP4 (s) + 6Cl2 (g) → 4PCl3 (g)      ΔH = -1225.6 kJP4 (s) + 5O2 (g) → P4O10 (s)      ΔH = -2967.3 kJPCl3 (g) + Cl2 (g) → PCl5 (g)      ΔH = -84.2 kJPCl3 (g) + 1/2 O2 (g) → Cl3PO

Problem

Given the following data

P4 (s) + 6Cl2 (g) → 4PCl3 (g)      ΔH = -1225.6 kJ

P4 (s) + 5O2 (g) → P4O10 (s)      ΔH = -2967.3 kJ

PCl3 (g) + Cl2 (g) → PCl5 (g)      ΔH = -84.2 kJ

PCl3 (g) + 1/2 O2 (g) → Cl3PO (g)    ΔH = -285.7 kJ

calculate ΔH for the reaction

P4O10 (s) + 6PCl5 (g) → 10Cl3PO (g)