Ch.6 - Thermochemistry WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Calculate ΔH for the reaction2NH3 (g) + 1/2 O2 (g) → N2H4 (l) + H2O (l) given the following data:2NH3 (g) + 3N2O (g) → 4N2 (g) + 3H2O (l)  ΔH = -1010 kJN2O (g) + 3H2 (g) → N2H4 (l) + H2O (l)      ΔH = -317 kJN2H4(l) + O2 (g) → N2(g) + 2H2O (l)      ΔH = -623 kJH2(g) + 1/2O2 (g) → H2O (l)          ΔH = -286 kJ

Solution: Calculate ΔH for the reaction2NH3 (g) + 1/2 O2 (g) → N2H4 (l) + H2O (l) given the following data:2NH3 (g) + 3N2O (g) → 4N2 (g) + 3H2O (l)  ΔH = -1010 kJN2O (g) + 3H2 (g) → N2H4 (l) + H2O (l)      ΔH =

Problem

Calculate ΔH for the reaction

2NH3 (g) + 1/2 O2 (g) → N2H4 (l) + H2O (l) 

given the following data:

2NH3 (g) + 3N2O (g) → 4N2 (g) + 3H2O (l)  ΔH = -1010 kJ

N2O (g) + 3H2 (g) → N2H4 (l) + H2O (l)      ΔH = -317 kJ

N2H4(l) + O2 (g) → N2(g) + 2H2O (l)      ΔH = -623 kJ

H2(g) + 1/2O2 (g) → H2O (l)          ΔH = -286 kJ