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Solution: An important process for the production of acrylonitrile (C3H3N) is given by the following equation:2C3H6(g) + 2NH3(g) + 3O2(g) → 2C3H3N(g) + 6H2O(g)A 150.-L reactor is charged to the following partial pressures at 25°C:What mass of acrylonitrile can be produced from this mixture (MPa = 10 6 Pa)?

Problem

An important process for the production of acrylonitrile (C3H3N) is given by the following equation:

2C3H6(g) + 2NH3(g) + 3O2(g) → 2C3H3N(g) + 6H2O(g)

A 150.-L reactor is charged to the following partial pressures at 25°C:

What mass of acrylonitrile can be produced from this mixture (MPa = 10 6 Pa)?

Solution
  • According to the ideal gas equation, pressure is directly proportional to # of moles. (as P increases, n increases at constant V and T  (Avogadro's Law))
  • Therefore, whichever has the least amount of P will be considered as the limiting reactant. (C3H6 at 0.500 MPa). MPa here is a unit of P
  • Moles of the limiting reactant can be solved using the ideal gas equation and the conditions provided
  • Mass of acrylonitrile can be solved using this moles of limiting reactant and the balanced equation provided. 
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