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**Given:**

**T = 25 °C + 273.15 = 298.15 K **

**Calculate for molar mass of methane (CH _{4}) in kg/mol:**

• molar mass of **N _{2}**:

• **1 kg = 10 ^{3} g**

${\mathbf{M}}_{{\mathbf{N}}_{\mathbf{2}}}\mathbf{=}\mathbf{28}\mathbf{.}\mathbf{02}\mathbf{}\frac{\overline{)\mathbf{g}}}{\mathbf{mol}}\mathbf{}\mathbf{\times}\mathbf{}\frac{\mathbf{1}\mathbf{}\mathbf{kg}}{{\mathbf{10}}^{\mathbf{3}}\mathbf{}\overline{)\mathbf{g}}}$

${\mathbf{M}}_{{\mathbf{N}}_{\mathbf{2}}}\mathbf{=}$**0.02802 kg/mol**

The root mean square speed of H_{2} molecules at 25 °C is about 1.6 km/s. What is the root mean square speed of a N_{2} molecule at 25 °C?

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Based on our data, we think this problem is relevant for Professor Fakhreddine's class at TEXAS.

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Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.